![]() ![]() There are two square bases and 4 rectangular faces so the total area is 2 $\times$ 1 4 $\times$ 3 = 14 square inches. To calculate the surface area of this rectangular prism we add the areas of the square bases (1 square inch each) to the areas of the rectangular faces (3 square inches each). ![]() There are other possible nets as well, such as the one pictured below:Įach square is one inch by one inch and each rectangle is 3 inches by 1 inch. We could, for example, leave the four rectangles one on top of the other as in the picture above and move the two square bases: the only restraint is that they need to share a side with one of the four rectangles and they cannot both be on the left or both be on the right. There are many different nets for this rectangular prism. So all four triangular faces have an area of 12 square units, and the total surface area of the pyramid is 4 12 = 16 square units. ![]() Since each base is 2 units and each height is 3 units the  area of one triangle is $\frac \times 2 \times 3 = 3$ square units. The four faces of the pyramid all have the same area. The net of a rectangular prism consists of six. The area of the square base will be 4 square units. Explore
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